Base | Representation |
---|---|
bin | 10010101010011111… |
… | …01100001110010011 |
3 | 221212022121101120112 |
4 | 21111033230032103 |
5 | 131010122030001 |
6 | 4334141431535 |
7 | 503210353223 |
oct | 112517541623 |
9 | 27768541515 |
10 | 10020111251 |
11 | 4282100987 |
12 | 1b3786b5ab |
13 | c38c0c417 |
14 | 6b0aba083 |
15 | 3d9a31cbb |
hex | 2553ec393 |
10020111251 has 2 divisors, whose sum is σ = 10020111252. Its totient is φ = 10020111250.
The previous prime is 10020111239. The next prime is 10020111271. The reversal of 10020111251 is 15211102001.
It is a weak prime.
It is an emirp because it is prime and its reverse (15211102001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10020111251 - 210 = 10020110227 is a prime.
It is not a weakly prime, because it can be changed into another prime (10020111271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010055625 + 5010055626.
It is an arithmetic number, because the mean of its divisors is an integer number (5010055626).
Almost surely, 210020111251 is an apocalyptic number.
10020111251 is a deficient number, since it is larger than the sum of its proper divisors (1).
10020111251 is an equidigital number, since it uses as much as digits as its factorization.
10020111251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 10020111251 its reverse (15211102001), we get a palindrome (25231213252).
The spelling of 10020111251 in words is "ten billion, twenty million, one hundred eleven thousand, two hundred fifty-one".
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