100201211012013 has 4 divisors (see below), whose sum is σ = 133601614682688. Its totient is φ = 66800807341340.

The previous prime is 100201211011933. The next prime is 100201211012033. The reversal of 100201211012013 is 310210112102001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100201211012013 - 2⁸ = 100201211011757 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100201211011983 and 100201211012001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100201211012033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16700201835333 + ... + 16700201835338.

It is an arithmetic number, because the mean of its divisors is an integer number (33400403670672).

Almost surely, 2^{100201211012013} is an apocalyptic number.

It is an amenable number.

100201211012013 is a deficient number, since it is larger than the sum of its proper divisors (33400403670675).

100201211012013 is an equidigital number, since it uses as much as digits as its factorization.

100201211012013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33400403670674.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 100201211012013 its reverse (310210112102001), we get a palindrome (410411323114014).

The spelling of 100201211012013 in words is "one hundred trillion, two hundred one billion, two hundred eleven million, twelve thousand, thirteen".