Base | Representation |
---|---|
bin | 1001000111001111110111… |
… | …0000111100110111101001 |
3 | 1022110220200110211020011202 |
4 | 2101303331300330313221 |
5 | 2303132202011432103 |
6 | 33151102524133545 |
7 | 2052633641630246 |
oct | 221637560746751 |
9 | 38426613736152 |
10 | 10020121202153 |
11 | 3213567216007 |
12 | 1159b723972b5 |
13 | 578b7c98b2ba |
14 | 268d955645cd |
15 | 1259a6650988 |
hex | 91cfdc3cde9 |
10020121202153 has 2 divisors, whose sum is σ = 10020121202154. Its totient is φ = 10020121202152.
The previous prime is 10020121202149. The next prime is 10020121202237. The reversal of 10020121202153 is 35120212102001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8392220806489 + 1627900395664 = 2896933^2 + 1275892^2 .
It is a cyclic number.
It is not a de Polignac number, because 10020121202153 - 22 = 10020121202149 is a prime.
It is not a weakly prime, because it can be changed into another prime (10020121202053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010060601076 + 5010060601077.
It is an arithmetic number, because the mean of its divisors is an integer number (5010060601077).
Almost surely, 210020121202153 is an apocalyptic number.
It is an amenable number.
10020121202153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10020121202153 is an equidigital number, since it uses as much as digits as its factorization.
10020121202153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 10020121202153 its reverse (35120212102001), we get a palindrome (45140333304154).
The spelling of 10020121202153 in words is "ten trillion, twenty billion, one hundred twenty-one million, two hundred two thousand, one hundred fifty-three".
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