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100201412321347 is a prime number
BaseRepresentation
bin10110110010000111110101…
…100101100110000001000011
3111010210011100201010120110011
4112302013311211212001003
5101113144443023240342
6553035520543445351
730051212256500221
oct2662076545460103
9433704321116404
10100201412321347
1129a221a90122a7
12b2a38562b6857
1343bac4cc38c0c
141aa5aba6d1b11
15b8b706c1e717
hex5b21f5966043

100201412321347 has 2 divisors, whose sum is σ = 100201412321348. Its totient is φ = 100201412321346.

The previous prime is 100201412321291. The next prime is 100201412321357. The reversal of 100201412321347 is 743123214102001.

It is a strong prime.

It is an emirp because it is prime and its reverse (743123214102001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100201412321347 - 231 = 100199264837699 is a prime.

It is not a weakly prime, because it can be changed into another prime (100201412321357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100706160673 + 50100706160674.

It is an arithmetic number, because the mean of its divisors is an integer number (50100706160674).

Almost surely, 2100201412321347 is an apocalyptic number.

100201412321347 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201412321347 is an equidigital number, since it uses as much as digits as its factorization.

100201412321347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 100201412321347 its reverse (743123214102001), we get a palindrome (843324626423348).

The spelling of 100201412321347 in words is "one hundred trillion, two hundred one billion, four hundred twelve million, three hundred twenty-one thousand, three hundred forty-seven".