Base | Representation |
---|---|
bin | 10110110010000111110101… |
… | …100101100110000001000011 |
3 | 111010210011100201010120110011 |
4 | 112302013311211212001003 |
5 | 101113144443023240342 |
6 | 553035520543445351 |
7 | 30051212256500221 |
oct | 2662076545460103 |
9 | 433704321116404 |
10 | 100201412321347 |
11 | 29a221a90122a7 |
12 | b2a38562b6857 |
13 | 43bac4cc38c0c |
14 | 1aa5aba6d1b11 |
15 | b8b706c1e717 |
hex | 5b21f5966043 |
100201412321347 has 2 divisors, whose sum is σ = 100201412321348. Its totient is φ = 100201412321346.
The previous prime is 100201412321291. The next prime is 100201412321357. The reversal of 100201412321347 is 743123214102001.
It is a strong prime.
It is an emirp because it is prime and its reverse (743123214102001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100201412321347 - 231 = 100199264837699 is a prime.
It is not a weakly prime, because it can be changed into another prime (100201412321357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100706160673 + 50100706160674.
It is an arithmetic number, because the mean of its divisors is an integer number (50100706160674).
Almost surely, 2100201412321347 is an apocalyptic number.
100201412321347 is a deficient number, since it is larger than the sum of its proper divisors (1).
100201412321347 is an equidigital number, since it uses as much as digits as its factorization.
100201412321347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 100201412321347 its reverse (743123214102001), we get a palindrome (843324626423348).
The spelling of 100201412321347 in words is "one hundred trillion, two hundred one billion, four hundred twelve million, three hundred twenty-one thousand, three hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •