Base | Representation |
---|---|
bin | 11101001010011010001… |
… | …10110001001111000011 |
3 | 10112210101120021212110202 |
4 | 32211031012301033003 |
5 | 112404114334001011 |
6 | 2044153323315415 |
7 | 132252004653464 |
oct | 16451506611703 |
9 | 3483346255422 |
10 | 1002021000131 |
11 | 356a55806238 |
12 | 14224697bb6b |
13 | 7364abb65c8 |
14 | 366d8a0ad6b |
15 | 1b0e8dc623b |
hex | e94d1b13c3 |
1002021000131 has 2 divisors, whose sum is σ = 1002021000132. Its totient is φ = 1002021000130.
The previous prime is 1002021000103. The next prime is 1002021000221. The reversal of 1002021000131 is 1310001202001.
1002021000131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1002021000131 is a prime.
It is a super-2 number, since 2×10020210001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1002021000931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501010500065 + 501010500066.
It is an arithmetic number, because the mean of its divisors is an integer number (501010500066).
Almost surely, 21002021000131 is an apocalyptic number.
1002021000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002021000131 is an equidigital number, since it uses as much as digits as its factorization.
1002021000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 1002021000131 its reverse (1310001202001), we get a palindrome (2312022202132).
The spelling of 1002021000131 in words is "one trillion, two billion, twenty-one million, one hundred thirty-one", and thus it is an aban number.
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