Base | Representation |
---|---|
bin | 10110110010010000000010… |
… | …000010101001110000110011 |
3 | 111010211000001220202220220121 |
4 | 112302100002002221300303 |
5 | 101113321003031400201 |
6 | 553043534022151111 |
7 | 30051643310643631 |
oct | 2662200202516063 |
9 | 433730056686817 |
10 | 100210211200051 |
11 | 29a25a03825087 |
12 | b2a54b0b82497 |
13 | 43bba22b2b714 |
14 | 1aa62b3112351 |
15 | b8ba6e41e9a1 |
hex | 5b24020a9c33 |
100210211200051 has 2 divisors, whose sum is σ = 100210211200052. Its totient is φ = 100210211200050.
The previous prime is 100210211199947. The next prime is 100210211200091. The reversal of 100210211200051 is 150002112012001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100210211200051 - 223 = 100210202811443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100210211199998 and 100210211200034.
It is not a weakly prime, because it can be changed into another prime (100210211200091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50105105600025 + 50105105600026.
It is an arithmetic number, because the mean of its divisors is an integer number (50105105600026).
Almost surely, 2100210211200051 is an apocalyptic number.
100210211200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
100210211200051 is an equidigital number, since it uses as much as digits as its factorization.
100210211200051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 100210211200051 its reverse (150002112012001), we get a palindrome (250212323212052).
The spelling of 100210211200051 in words is "one hundred trillion, two hundred ten billion, two hundred eleven million, two hundred thousand, fifty-one".
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