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100211202102083 is a prime number
BaseRepresentation
bin10110110010010000111101…
…000110101001001101000011
3111010211002121222022221221212
4112302100331012221031003
5101113330020214231313
6553044220220440335
730052010002323062
oct2662207506511503
9433732558287855
10100211202102083
1129a263720a4486
12b2a57289a90ab
1343bbb50201797
141aa63689721d9
15b8bacb4053a8
hex5b243d1a9343

100211202102083 has 2 divisors, whose sum is σ = 100211202102084. Its totient is φ = 100211202102082.

The previous prime is 100211202101963. The next prime is 100211202102161. The reversal of 100211202102083 is 380201202112001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100211202102083 - 230 = 100210128360259 is a prime.

It is a super-5 number, since 5×1002112021020835 (a number of 71 digits) contains 55555 as substring.

It is not a weakly prime, because it can be changed into another prime (100211202102383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50105601051041 + 50105601051042.

It is an arithmetic number, because the mean of its divisors is an integer number (50105601051042).

Almost surely, 2100211202102083 is an apocalyptic number.

100211202102083 is a deficient number, since it is larger than the sum of its proper divisors (1).

100211202102083 is an equidigital number, since it uses as much as digits as its factorization.

100211202102083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 100211202102083 its reverse (380201202112001), we get a palindrome (480412404214084).

The spelling of 100211202102083 in words is "one hundred trillion, two hundred eleven billion, two hundred two million, one hundred two thousand, eighty-three".