Base | Representation |
---|---|
bin | 1001000111010011111010… |
… | …1011001001011111001011 |
3 | 1022111000111100222001101202 |
4 | 2101310332223021133023 |
5 | 2303141414302400021 |
6 | 33151402545134415 |
7 | 2053002634151153 |
oct | 221647653113713 |
9 | 38430440861352 |
10 | 10021210200011 |
11 | 3213a759a623a |
12 | 115a21702a40b |
13 | 578cc448922a |
14 | 26905a03b763 |
15 | 125a1c061a0b |
hex | 91d3eac97cb |
10021210200011 has 2 divisors, whose sum is σ = 10021210200012. Its totient is φ = 10021210200010.
The previous prime is 10021210199971. The next prime is 10021210200037. The reversal of 10021210200011 is 11000201212001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10021210200011 - 214 = 10021210183627 is a prime.
It is a super-4 number, since 4×100212102000114 (a number of 53 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10021210199965 and 10021210200001.
It is not a weakly prime, because it can be changed into another prime (10021210200811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010605100005 + 5010605100006.
It is an arithmetic number, because the mean of its divisors is an integer number (5010605100006).
Almost surely, 210021210200011 is an apocalyptic number.
10021210200011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10021210200011 is an equidigital number, since it uses as much as digits as its factorization.
10021210200011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 10021210200011 its reverse (11000201212001), we get a palindrome (21021411412012).
The spelling of 10021210200011 in words is "ten trillion, twenty-one billion, two hundred ten million, two hundred thousand, eleven".
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