Base | Representation |
---|---|
bin | 10110110010010001110010… |
… | …101111111100100000011011 |
3 | 111010211011221200212200111022 |
4 | 112302101302233330200123 |
5 | 101113333341120341444 |
6 | 553044445411153055 |
7 | 30052041211342304 |
oct | 2662216257744033 |
9 | 433734850780438 |
10 | 100212102121499 |
11 | 29a2679413a385 |
12 | b2a593a2a578b |
13 | 43bbc64803c54 |
14 | 1aa64122d57ab |
15 | b8bb304379ee |
hex | 5b2472bfc81b |
100212102121499 has 2 divisors, whose sum is σ = 100212102121500. Its totient is φ = 100212102121498.
The previous prime is 100212102121463. The next prime is 100212102121519. The reversal of 100212102121499 is 994121201212001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100212102121499 is a prime.
It is not a weakly prime, because it can be changed into another prime (100212102121099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106051060749 + 50106051060750.
It is an arithmetic number, because the mean of its divisors is an integer number (50106051060750).
Almost surely, 2100212102121499 is an apocalyptic number.
100212102121499 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212102121499 is an equidigital number, since it uses as much as digits as its factorization.
100212102121499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 100212102121499 in words is "one hundred trillion, two hundred twelve billion, one hundred two million, one hundred twenty-one thousand, four hundred ninety-nine".
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