10021231431133 has 4 divisors (see below), whose sum is σ = 10792095387388. Its totient is φ = 9250367474880.

The previous prime is 10021231431103. The next prime is 10021231431181. The reversal of 10021231431133 is 33113413212001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4121375033689 + 5899856397444 = 2030117^2 + 2428962^2 .

It is a cyclic number.

It is not a de Polignac number, because 10021231431133 - 2²⁹ = 10020694560221 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10021231431098 and 10021231431107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10021231431103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385431978108 + ... + 385431978133.

It is an arithmetic number, because the mean of its divisors is an integer number (2698023846847).

Almost surely, 2^{10021231431133} is an apocalyptic number.

10021231431133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10021231431133 is a deficient number, since it is larger than the sum of its proper divisors (770863956255).

10021231431133 is an equidigital number, since it uses as much as digits as its factorization.

10021231431133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 770863956254.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 10021231431133 its reverse (33113413212001), we get a palindrome (43134644643134).

The spelling of 10021231431133 in words is "ten trillion, twenty-one billion, two hundred thirty-one million, four hundred thirty-one thousand, one hundred thirty-three".