Base | Representation |
---|---|
bin | 11101001010101010000… |
… | …11011100000000110001 |
3 | 10112210201212012110112222 |
4 | 32211111003130000301 |
5 | 112404403003010442 |
6 | 2044214445330425 |
7 | 132255214243535 |
oct | 16452503340061 |
9 | 3483655173488 |
10 | 1002154344497 |
11 | 357014001899 |
12 | 142283566a15 |
13 | 7366c7033b7 |
14 | 3670c5dbbc5 |
15 | 1b1059658d2 |
hex | e9550dc031 |
1002154344497 has 2 divisors, whose sum is σ = 1002154344498. Its totient is φ = 1002154344496.
The previous prime is 1002154344491. The next prime is 1002154344509. The reversal of 1002154344497 is 7944434512001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 653719143841 + 348435200656 = 808529^2 + 590284^2 .
It is a cyclic number.
It is not a de Polignac number, because 1002154344497 - 238 = 727276437553 is a prime.
It is not a weakly prime, because it can be changed into another prime (1002154344491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501077172248 + 501077172249.
It is an arithmetic number, because the mean of its divisors is an integer number (501077172249).
Almost surely, 21002154344497 is an apocalyptic number.
It is an amenable number.
1002154344497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002154344497 is an equidigital number, since it uses as much as digits as its factorization.
1002154344497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 483840, while the sum is 44.
Adding to 1002154344497 its reverse (7944434512001), we get a palindrome (8946588856498).
The spelling of 1002154344497 in words is "one trillion, two billion, one hundred fifty-four million, three hundred forty-four thousand, four hundred ninety-seven".
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