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100220112314 = 277158579451
BaseRepresentation
bin101110101010110010…
…1011000110110111010
3100120200111211012120122
41131111211120312322
53120222322043224
6114012424453242
710145355620240
oct1352545306672
9316614735518
10100220112314
1139559705803
121750b61a222
1395b22b930a
144bca39a790
15291871815e
hex1755958dba

100220112314 has 8 divisors (see below), whose sum is σ = 171805906848. Its totient is φ = 42951476700.

The previous prime is 100220112299. The next prime is 100220112329. The reversal of 100220112314 is 413211022001.

It is an interprime number because it is at equal distance from previous prime (100220112299) and next prime (100220112329).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 100220112292 and 100220112301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3579289712 + ... + 3579289739.

It is an arithmetic number, because the mean of its divisors is an integer number (21475738356).

Almost surely, 2100220112314 is an apocalyptic number.

100220112314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

100220112314 is a deficient number, since it is larger than the sum of its proper divisors (71585794534).

100220112314 is an equidigital number, since it uses as much as digits as its factorization.

100220112314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7158579460.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 100220112314 its reverse (413211022001), we get a palindrome (513431134315).

The spelling of 100220112314 in words is "one hundred billion, two hundred twenty million, one hundred twelve thousand, three hundred fourteen".

Divisors: 1 2 7 14 7158579451 14317158902 50110056157 100220112314