Base | Representation |
---|---|
bin | 101110101010110010… |
… | …1011011000101101011 |
3 | 100120200111211200010001 |
4 | 1131111211123011223 |
5 | 3120222322341301 |
6 | 114012425003431 |
7 | 10145355656002 |
oct | 1352545330553 |
9 | 316614750101 |
10 | 100220121451 |
11 | 3955971165a |
12 | 1750b623577 |
13 | 95b22c0518 |
14 | 4bca39dc39 |
15 | 291871ac01 |
hex | 175595b16b |
100220121451 has 2 divisors, whose sum is σ = 100220121452. Its totient is φ = 100220121450.
The previous prime is 100220121359. The next prime is 100220121467. The reversal of 100220121451 is 154121022001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100220121451 - 211 = 100220119403 is a prime.
It is not a weakly prime, because it can be changed into another prime (100220121751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50110060725 + 50110060726.
It is an arithmetic number, because the mean of its divisors is an integer number (50110060726).
Almost surely, 2100220121451 is an apocalyptic number.
100220121451 is a deficient number, since it is larger than the sum of its proper divisors (1).
100220121451 is an equidigital number, since it uses as much as digits as its factorization.
100220121451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 100220121451 its reverse (154121022001), we get a palindrome (254341143452).
The spelling of 100220121451 in words is "one hundred billion, two hundred twenty million, one hundred twenty-one thousand, four hundred fifty-one".
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