Base | Representation |
---|---|
bin | 1001000111010111010010… |
… | …0000010000010101010011 |
3 | 1022111002211022100000001212 |
4 | 2101311310200100111103 |
5 | 2303200242002023011 |
6 | 33152032330050335 |
7 | 2053034211410012 |
oct | 221656440202523 |
9 | 38432738300055 |
10 | 10022113314131 |
11 | 3214399765246 |
12 | 115a4295799ab |
13 | 579109603199 |
14 | 269103d68a79 |
15 | 125a714a608b |
hex | 91d74810553 |
10022113314131 has 2 divisors, whose sum is σ = 10022113314132. Its totient is φ = 10022113314130.
The previous prime is 10022113314107. The next prime is 10022113314139. The reversal of 10022113314131 is 13141331122001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10022113314131 - 26 = 10022113314067 is a prime.
It is a super-2 number, since 2×100221133141312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10022113314097 and 10022113314106.
It is not a weakly prime, because it can be changed into another prime (10022113314139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011056657065 + 5011056657066.
It is an arithmetic number, because the mean of its divisors is an integer number (5011056657066).
Almost surely, 210022113314131 is an apocalyptic number.
10022113314131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10022113314131 is an equidigital number, since it uses as much as digits as its factorization.
10022113314131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 10022113314131 its reverse (13141331122001), we get a palindrome (23163444436132).
The spelling of 10022113314131 in words is "ten trillion, twenty-two billion, one hundred thirteen million, three hundred fourteen thousand, one hundred thirty-one".
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