Base | Representation |
---|---|
bin | 101110101010110110… |
… | …1010111000110101001 |
3 | 100120200122202101110211 |
4 | 1131111231113012221 |
5 | 3120223340433111 |
6 | 114012541341121 |
7 | 10145412443365 |
oct | 1352555270651 |
9 | 316618671424 |
10 | 100222202281 |
11 | 3955a902a53 |
12 | 175102677a1 |
13 | 95b286b696 |
14 | 4bca7822a5 |
15 | 29189cc521 |
hex | 1755b571a9 |
100222202281 has 2 divisors, whose sum is σ = 100222202282. Its totient is φ = 100222202280.
The previous prime is 100222202239. The next prime is 100222202287. The reversal of 100222202281 is 182202222001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67852435225 + 32369767056 = 260485^2 + 179916^2 .
It is an emirp because it is prime and its reverse (182202222001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100222202281 - 221 = 100220105129 is a prime.
It is a super-2 number, since 2×1002222022812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100222202287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50111101140 + 50111101141.
It is an arithmetic number, because the mean of its divisors is an integer number (50111101141).
Almost surely, 2100222202281 is an apocalyptic number.
It is an amenable number.
100222202281 is a deficient number, since it is larger than the sum of its proper divisors (1).
100222202281 is an equidigital number, since it uses as much as digits as its factorization.
100222202281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 22.
Adding to 100222202281 its reverse (182202222001), we get a palindrome (282424424282).
The spelling of 100222202281 in words is "one hundred billion, two hundred twenty-two million, two hundred two thousand, two hundred eighty-one".
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