Search a number
-
+
100230121422113 is a prime number
BaseRepresentation
bin10110110010100010100100…
…110010000111110100100001
3111010212220110111100222222112
4112302202210302013310201
5101114132242041001423
6553101025423245105
730053246563021364
oct2662424462076441
9433786414328875
10100230121422113
1129a333a0604661
12b2a9328a49795
1343c0876a314c7
141aa72415080db
15b8c337354a78
hex5b28a4c87d21

100230121422113 has 2 divisors, whose sum is σ = 100230121422114. Its totient is φ = 100230121422112.

The previous prime is 100230121422043. The next prime is 100230121422121. The reversal of 100230121422113 is 311224121032001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73260452429824 + 26969668992289 = 8559232^2 + 5193233^2 .

It is a cyclic number.

It is not a de Polignac number, because 100230121422113 - 228 = 100229852986657 is a prime.

It is a super-3 number, since 3×1002301214221133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (100230121422413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50115060711056 + 50115060711057.

It is an arithmetic number, because the mean of its divisors is an integer number (50115060711057).

Almost surely, 2100230121422113 is an apocalyptic number.

It is an amenable number.

100230121422113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100230121422113 is an equidigital number, since it uses as much as digits as its factorization.

100230121422113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 100230121422113 its reverse (311224121032001), we get a palindrome (411454242454114).

The spelling of 100230121422113 in words is "one hundred trillion, two hundred thirty billion, one hundred twenty-one million, four hundred twenty-two thousand, one hundred thirteen".