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100231312033 is a prime number
BaseRepresentation
bin101110101011001000…
…0000111001010100001
3100120201021220012201001
41131112100013022201
53120233203441113
6114013504512001
710145553044416
oct1352620071241
9316637805631
10100231312033
1139564a65276
121751331b601
1395b470ac78
144bcba7410d
1529196cb7dd
hex17564072a1

100231312033 has 2 divisors, whose sum is σ = 100231312034. Its totient is φ = 100231312032.

The previous prime is 100231312021. The next prime is 100231312063. The reversal of 100231312033 is 330213132001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71474953104 + 28756358929 = 267348^2 + 169577^2 .

It is an emirp because it is prime and its reverse (330213132001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100231312033 - 217 = 100231180961 is a prime.

It is a super-2 number, since 2×1002313120332 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100231312033.

It is not a weakly prime, because it can be changed into another prime (100231312063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50115656016 + 50115656017.

It is an arithmetic number, because the mean of its divisors is an integer number (50115656017).

Almost surely, 2100231312033 is an apocalyptic number.

It is an amenable number.

100231312033 is a deficient number, since it is larger than the sum of its proper divisors (1).

100231312033 is an equidigital number, since it uses as much as digits as its factorization.

100231312033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 100231312033 its reverse (330213132001), we get a palindrome (430444444034).

The spelling of 100231312033 in words is "one hundred billion, two hundred thirty-one million, three hundred twelve thousand, thirty-three".