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10023312113 is a prime number
BaseRepresentation
bin10010101010110111…
…11001101011110001
3221212112122000022222
421111123321223301
5131011431441423
64334334210425
7503246514203
oct112533715361
927775560288
1010023312113
114283997821
121b38953a15
13c39790319
146b12b0773
153d9e653c8
hex2556f9af1

10023312113 has 2 divisors, whose sum is σ = 10023312114. Its totient is φ = 10023312112.

The previous prime is 10023312097. The next prime is 10023312179. The reversal of 10023312113 is 31121332001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9188564449 + 834747664 = 95857^2 + 28892^2 .

It is a cyclic number.

It is not a de Polignac number, because 10023312113 - 24 = 10023312097 is a prime.

It is a super-2 number, since 2×100233121132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10023312091 and 10023312100.

It is not a weakly prime, because it can be changed into another prime (10023312613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011656056 + 5011656057.

It is an arithmetic number, because the mean of its divisors is an integer number (5011656057).

Almost surely, 210023312113 is an apocalyptic number.

It is an amenable number.

10023312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10023312113 is an equidigital number, since it uses as much as digits as its factorization.

10023312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10023312113 its reverse (31121332001), we get a palindrome (41144644114).

The spelling of 10023312113 in words is "ten billion, twenty-three million, three hundred twelve thousand, one hundred thirteen".