Base | Representation |
---|---|
bin | 10010101010111111… |
… | …01110001001100001 |
3 | 221212121111212220012 |
4 | 21111133232021201 |
5 | 131012211012231 |
6 | 4334411454305 |
7 | 503261154422 |
oct | 112537561141 |
9 | 27777455805 |
10 | 10024313441 |
11 | 428451106a |
12 | 1b39157395 |
13 | c39a5101c |
14 | 6b1491649 |
15 | 3da0b1e2b |
hex | 2557ee261 |
10024313441 has 2 divisors, whose sum is σ = 10024313442. Its totient is φ = 10024313440.
The previous prime is 10024313413. The next prime is 10024313459. The reversal of 10024313441 is 14431342001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9996000400 + 28313041 = 99980^2 + 5321^2 .
It is an emirp because it is prime and its reverse (14431342001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10024313441 - 226 = 9957204577 is a prime.
It is not a weakly prime, because it can be changed into another prime (10024313461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012156720 + 5012156721.
It is an arithmetic number, because the mean of its divisors is an integer number (5012156721).
Almost surely, 210024313441 is an apocalyptic number.
It is an amenable number.
10024313441 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024313441 is an equidigital number, since it uses as much as digits as its factorization.
10024313441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 10024313441 its reverse (14431342001), we get a palindrome (24455655442).
The spelling of 10024313441 in words is "ten billion, twenty-four million, three hundred thirteen thousand, four hundred forty-one".
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