Base | Representation |
---|---|
bin | 101110101011100001… |
… | …0001010000101101011 |
3 | 100120202012120201211112 |
4 | 1131113002022011223 |
5 | 3120300033244321 |
6 | 114015054020535 |
7 | 10146102414641 |
oct | 1352702120553 |
9 | 316665521745 |
10 | 100244431211 |
11 | 39571405971 |
12 | 175177a774b |
13 | 95b73524b2 |
14 | 4bcd6cb191 |
15 | 291a91da5b |
hex | 175708a16b |
100244431211 has 2 divisors, whose sum is σ = 100244431212. Its totient is φ = 100244431210.
The previous prime is 100244431193. The next prime is 100244431303. The reversal of 100244431211 is 112134442001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100244431211 is a prime.
It is not a weakly prime, because it can be changed into another prime (100244431411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50122215605 + 50122215606.
It is an arithmetic number, because the mean of its divisors is an integer number (50122215606).
Almost surely, 2100244431211 is an apocalyptic number.
100244431211 is a deficient number, since it is larger than the sum of its proper divisors (1).
100244431211 is an equidigital number, since it uses as much as digits as its factorization.
100244431211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 100244431211 its reverse (112134442001), we get a palindrome (212378873212).
The spelling of 100244431211 in words is "one hundred billion, two hundred forty-four million, four hundred thirty-one thousand, two hundred eleven".
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