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100256131 is a prime number
BaseRepresentation
bin1011111100111…
…00100110000011
320222122112120001
411332130212003
5201131144011
613540500431
72325106633
oct576344603
9228575501
10100256131
1151656a08
12296aa717
1317a03271
14d45a6c3
158c057c1
hex5f9c983

100256131 has 2 divisors, whose sum is σ = 100256132. Its totient is φ = 100256130.

The previous prime is 100256119. The next prime is 100256147. The reversal of 100256131 is 131652001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100256131 - 25 = 100256099 is a prime.

It is a super-2 number, since 2×1002561312 = 20102583606178322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100256099 and 100256108.

It is not a weakly prime, because it can be changed into another prime (100256831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50128065 + 50128066.

It is an arithmetic number, because the mean of its divisors is an integer number (50128066).

Almost surely, 2100256131 is an apocalyptic number.

100256131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100256131 is an equidigital number, since it uses as much as digits as its factorization.

100256131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 100256131 is about 10012.7983600989. The cubic root of 100256131 is about 464.5548304356.

The spelling of 100256131 in words is "one hundred million, two hundred fifty-six thousand, one hundred thirty-one".