Base | Representation |
---|---|
bin | 11101001011100010010… |
… | …00101101100011110011 |
3 | 10112211221200202002111112 |
4 | 32211301020231203303 |
5 | 112411334111123024 |
6 | 2044333315503535 |
7 | 132302665020221 |
oct | 16456110554363 |
9 | 3484850662445 |
10 | 1002625489139 |
11 | 357235a4a82a |
12 | 1423952b7bab |
13 | 737161c4501 |
14 | 36755001b11 |
15 | 1b131ece00e |
hex | e97122d8f3 |
1002625489139 has 2 divisors, whose sum is σ = 1002625489140. Its totient is φ = 1002625489138.
The previous prime is 1002625489091. The next prime is 1002625489183. The reversal of 1002625489139 is 9319845262001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002625489139 - 28 = 1002625488883 is a prime.
It is a super-2 number, since 2×10026254891392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1002625489939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501312744569 + 501312744570.
It is an arithmetic number, because the mean of its divisors is an integer number (501312744570).
Almost surely, 21002625489139 is an apocalyptic number.
1002625489139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002625489139 is an equidigital number, since it uses as much as digits as its factorization.
1002625489139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 50.
The spelling of 1002625489139 in words is "one trillion, two billion, six hundred twenty-five million, four hundred eighty-nine thousand, one hundred thirty-nine".
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