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100300113103 = 591700001917
BaseRepresentation
bin101110101101001011…
…0100100010011001111
3100120220002100200000211
41131122112210103033
53120403312104403
6114024403303251
710150346615551
oct1353226442317
9316802320024
10100300113103
113959a887563
121753237ab27
1395c5a49b68
144bd6c634d1
15292076c06d
hex175a5a44cf

100300113103 has 4 divisors (see below), whose sum is σ = 102000115080. Its totient is φ = 98600111128.

The previous prime is 100300113083. The next prime is 100300113113. The reversal of 100300113103 is 301311003001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100300113103 - 213 = 100300104911 is a prime.

It is a super-2 number, since 2×1003001131032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100300113113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850000900 + ... + 850001017.

It is an arithmetic number, because the mean of its divisors is an integer number (25500028770).

Almost surely, 2100300113103 is an apocalyptic number.

100300113103 is a deficient number, since it is larger than the sum of its proper divisors (1700001977).

100300113103 is an equidigital number, since it uses as much as digits as its factorization.

100300113103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1700001976.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 100300113103 its reverse (301311003001), we get a palindrome (401611116104).

The spelling of 100300113103 in words is "one hundred billion, three hundred million, one hundred thirteen thousand, one hundred three".

Divisors: 1 59 1700001917 100300113103