Base | Representation |
---|---|
bin | 1001000111110100101101… |
… | …0100111000101010000011 |
3 | 1022111212012210212020222012 |
4 | 2101331023110320222003 |
5 | 2303312431133333212 |
6 | 33155420223003135 |
7 | 2053434025506422 |
oct | 221751324705203 |
9 | 38455183766865 |
10 | 10030012402307 |
11 | 3217782579097 |
12 | 115ba72a394ab |
13 | 579a97c73761 |
14 | 2696530852b9 |
15 | 125d84bbb922 |
hex | 91f4b538a83 |
10030012402307 has 2 divisors, whose sum is σ = 10030012402308. Its totient is φ = 10030012402306.
The previous prime is 10030012402279. The next prime is 10030012402313. The reversal of 10030012402307 is 70320421003001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10030012402307 - 242 = 5631965891203 is a prime.
It is a super-2 number, since 2×100300124023072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10030012402327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015006201153 + 5015006201154.
It is an arithmetic number, because the mean of its divisors is an integer number (5015006201154).
Almost surely, 210030012402307 is an apocalyptic number.
10030012402307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10030012402307 is an equidigital number, since it uses as much as digits as its factorization.
10030012402307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 23.
Adding to 10030012402307 its reverse (70320421003001), we get a palindrome (80350433405308).
The spelling of 10030012402307 in words is "ten trillion, thirty billion, twelve million, four hundred two thousand, three hundred seven".
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