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10030012402307 is a prime number
BaseRepresentation
bin1001000111110100101101…
…0100111000101010000011
31022111212012210212020222012
42101331023110320222003
52303312431133333212
633155420223003135
72053434025506422
oct221751324705203
938455183766865
1010030012402307
113217782579097
12115ba72a394ab
13579a97c73761
142696530852b9
15125d84bbb922
hex91f4b538a83

10030012402307 has 2 divisors, whose sum is σ = 10030012402308. Its totient is φ = 10030012402306.

The previous prime is 10030012402279. The next prime is 10030012402313. The reversal of 10030012402307 is 70320421003001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10030012402307 - 242 = 5631965891203 is a prime.

It is a super-2 number, since 2×100300124023072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10030012402327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015006201153 + 5015006201154.

It is an arithmetic number, because the mean of its divisors is an integer number (5015006201154).

Almost surely, 210030012402307 is an apocalyptic number.

10030012402307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10030012402307 is an equidigital number, since it uses as much as digits as its factorization.

10030012402307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 23.

Adding to 10030012402307 its reverse (70320421003001), we get a palindrome (80350433405308).

The spelling of 10030012402307 in words is "ten trillion, thirty billion, twelve million, four hundred two thousand, three hundred seven".