Base | Representation |
---|---|
bin | 1001000111110111000011… |
… | …1100000000001111010010 |
3 | 1022111220211210012222020112 |
4 | 2101331300330000033102 |
5 | 2303320224203221340 |
6 | 33200003003441322 |
7 | 2053455460146524 |
oct | 221756074001722 |
9 | 38456753188215 |
10 | 10030643413970 |
11 | 3217a76788533 |
12 | 116000a226242 |
13 | 579b6890993a |
14 | 2696b2bc1a14 |
15 | 125dc02b3065 |
hex | 91f70f003d2 |
10030643413970 has 8 divisors (see below), whose sum is σ = 18055158145164. Its totient is φ = 4012257365584.
The previous prime is 10030643413831. The next prime is 10030643414009. The reversal of 10030643413970 is 7931434603001.
It can be written as a sum of positive squares in 2 ways, for example, as 8419868693401 + 1610774720569 = 2901701^2 + 1269163^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×100306434139703 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501532170689 + ... + 501532170708.
Almost surely, 210030643413970 is an apocalyptic number.
10030643413970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10030643413970 is a deficient number, since it is larger than the sum of its proper divisors (8024514731194).
10030643413970 is a wasteful number, since it uses less digits than its factorization.
10030643413970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1003064341404.
The product of its (nonzero) digits is 163296, while the sum is 41.
The spelling of 10030643413970 in words is "ten trillion, thirty billion, six hundred forty-three million, four hundred thirteen thousand, nine hundred seventy".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •