10031003103113 has 2 divisors, whose sum is σ = 10031003103114. Its totient is φ = 10031003103112.

The previous prime is 10031003103097. The next prime is 10031003103157. The reversal of 10031003103113 is 31130130013001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8629305754624 + 1401697348489 = 2937568^2 + 1183933^2 .

It is a cyclic number.

It is not a de Polignac number, because 10031003103113 - 2⁴ = 10031003103097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10031003103091 and 10031003103100.

It is not a weakly prime, because it can be changed into another prime (10031003103313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015501551556 + 5015501551557.

It is an arithmetic number, because the mean of its divisors is an integer number (5015501551557).

Almost surely, 2^{10031003103113} is an apocalyptic number.

It is an amenable number.

10031003103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10031003103113 is an equidigital number, since it uses as much as digits as its factorization.

10031003103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10031003103113 its reverse (31130130013001), we get a palindrome (41161133116114).

The spelling of 10031003103113 in words is "ten trillion, thirty-one billion, three million, one hundred three thousand, one hundred thirteen".