Base | Representation |
---|---|
bin | 10010101011110010… |
… | …10010100010110001 |
3 | 221220002010102020022 |
4 | 21111321102202301 |
5 | 131020420003423 |
6 | 4335211253225 |
7 | 503402141636 |
oct | 112571224261 |
9 | 27802112208 |
10 | 10031016113 |
11 | 4288279968 |
12 | 1b3b44a215 |
13 | c3b259ac1 |
14 | 6b231818d |
15 | 3da987dc8 |
hex | 255e528b1 |
10031016113 has 2 divisors, whose sum is σ = 10031016114. Its totient is φ = 10031016112.
The previous prime is 10031016109. The next prime is 10031016223. The reversal of 10031016113 is 31161013001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5252335729 + 4778680384 = 72473^2 + 69128^2 .
It is a cyclic number.
It is not a de Polignac number, because 10031016113 - 22 = 10031016109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10031016091 and 10031016100.
It is not a weakly prime, because it can be changed into another prime (10031016613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015508056 + 5015508057.
It is an arithmetic number, because the mean of its divisors is an integer number (5015508057).
Almost surely, 210031016113 is an apocalyptic number.
It is an amenable number.
10031016113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10031016113 is an equidigital number, since it uses as much as digits as its factorization.
10031016113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 10031016113 its reverse (31161013001), we get a palindrome (41192029114).
The spelling of 10031016113 in words is "ten billion, thirty-one million, sixteen thousand, one hundred thirteen".
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