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10031032513 is a prime number
BaseRepresentation
bin10010101011110010…
…10110100011000001
3221220002011020201201
421111321112203001
5131020421020023
64335211501201
7503402240515
oct112571264301
927802136651
1010031032513
114288290217
121b3b457801
13c3b2643c8
146b2320145
153da98cbad
hex255e568c1

10031032513 has 2 divisors, whose sum is σ = 10031032514. Its totient is φ = 10031032512.

The previous prime is 10031032507. The next prime is 10031032541. The reversal of 10031032513 is 31523013001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5528219904 + 4502812609 = 74352^2 + 67103^2 .

It is a cyclic number.

It is not a de Polignac number, because 10031032513 - 221 = 10028935361 is a prime.

It is a super-2 number, since 2×100310325132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10031032013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015516256 + 5015516257.

It is an arithmetic number, because the mean of its divisors is an integer number (5015516257).

Almost surely, 210031032513 is an apocalyptic number.

It is an amenable number.

10031032513 is a deficient number, since it is larger than the sum of its proper divisors (1).

10031032513 is an equidigital number, since it uses as much as digits as its factorization.

10031032513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 10031032513 its reverse (31523013001), we get a palindrome (41554045514).

The spelling of 10031032513 in words is "ten billion, thirty-one million, thirty-two thousand, five hundred thirteen".