100311330113 has 2 divisors, whose sum is σ = 100311330114. Its totient is φ = 100311330112.

The previous prime is 100311330101. The next prime is 100311330131. The reversal of 100311330113 is 311033113001.

Together with next prime (100311330131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72718133569 + 27593196544 = 269663^2 + 166112^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100311330113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100311330091 and 100311330100.

It is not a weakly prime, because it can be changed into another prime (100311330193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50155665056 + 50155665057.

It is an arithmetic number, because the mean of its divisors is an integer number (50155665057).

Almost surely, 2^100311330113 is an apocalyptic number.

It is an amenable number.

100311330113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100311330113 is an equidigital number, since it uses as much as digits as its factorization.

100311330113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 100311330113 its reverse (311033113001), we get a palindrome (411344443114).

The spelling of 100311330113 in words is "one hundred billion, three hundred eleven million, three hundred thirty thousand, one hundred thirteen".