Base | Representation |
---|---|
bin | 11101001100011100011… |
… | …01101110110100011001 |
3 | 10112220012200201200221111 |
4 | 32212032031232310121 |
5 | 112413334004004111 |
6 | 2044453544140321 |
7 | 132321040512346 |
oct | 16461615566431 |
9 | 3486180650844 |
10 | 1003113344281 |
11 | 3574663715a4 |
12 | 1424b07676a1 |
13 | 737932b66a9 |
14 | 3679db157cd |
15 | 1b15ec48a21 |
hex | e98e36ed19 |
1003113344281 has 2 divisors, whose sum is σ = 1003113344282. Its totient is φ = 1003113344280.
The previous prime is 1003113344197. The next prime is 1003113344323. The reversal of 1003113344281 is 1824433113001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 895122239881 + 107991104400 = 946109^2 + 328620^2 .
It is a cyclic number.
It is not a de Polignac number, because 1003113344281 - 211 = 1003113342233 is a prime.
It is a super-2 number, since 2×10031133442812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1003113344581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501556672140 + 501556672141.
It is an arithmetic number, because the mean of its divisors is an integer number (501556672141).
Almost surely, 21003113344281 is an apocalyptic number.
It is an amenable number.
1003113344281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003113344281 is an equidigital number, since it uses as much as digits as its factorization.
1003113344281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 1003113344281 its reverse (1824433113001), we get a palindrome (2827546457282).
The spelling of 1003113344281 in words is "one trillion, three billion, one hundred thirteen million, three hundred forty-four thousand, two hundred eighty-one".
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