Base | Representation |
---|---|
bin | 1001000111111000111010… |
… | …1110001111110100010101 |
3 | 1022111222010121111212212111 |
4 | 2101332032232033310111 |
5 | 2303322240114433440 |
6 | 33200124334151021 |
7 | 2053504035466015 |
oct | 221761656176425 |
9 | 38458117455774 |
10 | 10031143124245 |
11 | 3218202867231 |
12 | 1160129652471 |
13 | 579c182bcba9 |
14 | 26971d2ddc45 |
15 | 125dee0c04ea |
hex | 91f8eb8fd15 |
10031143124245 has 4 divisors (see below), whose sum is σ = 12037371749100. Its totient is φ = 8024914499392.
The previous prime is 10031143124221. The next prime is 10031143124279. The reversal of 10031143124245 is 54242134113001.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6336743909521 + 3694399214724 = 2517289^2 + 1922082^2 .
It is a cyclic number.
It is not a de Polignac number, because 10031143124245 - 29 = 10031143123733 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003114312420 + ... + 1003114312429.
It is an arithmetic number, because the mean of its divisors is an integer number (3009342937275).
Almost surely, 210031143124245 is an apocalyptic number.
It is an amenable number.
10031143124245 is a deficient number, since it is larger than the sum of its proper divisors (2006228624855).
10031143124245 is an equidigital number, since it uses as much as digits as its factorization.
10031143124245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2006228624854.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 10031143124245 its reverse (54242134113001), we get a palindrome (64273277237246).
The spelling of 10031143124245 in words is "ten trillion, thirty-one billion, one hundred forty-three million, one hundred twenty-four thousand, two hundred forty-five".
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