Base | Representation |
---|---|
bin | 101110101101100010… |
… | …0100000001111111011 |
3 | 100120220221000110120212 |
4 | 1131123010200033323 |
5 | 3120414402431011 |
6 | 114025513341335 |
7 | 10150554151526 |
oct | 1353304401773 |
9 | 316827013525 |
10 | 100312155131 |
11 | 395a6661951 |
12 | 1753640784b |
13 | 95c83a5016 |
14 | 4bd86b9bbd |
15 | 292184a08b |
hex | 175b1203fb |
100312155131 has 32 divisors (see below), whose sum is σ = 106409825280. Its totient is φ = 94459405824.
The previous prime is 100312155077. The next prime is 100312155133. The reversal of 100312155131 is 131551213001.
It is not a de Polignac number, because 100312155131 - 26 = 100312155067 is a prime.
It is a super-2 number, since 2×1003121551312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100312155097 and 100312155106.
It is not an unprimeable number, because it can be changed into a prime (100312155133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39507260 + ... + 39509798.
It is an arithmetic number, because the mean of its divisors is an integer number (3325307040).
Almost surely, 2100312155131 is an apocalyptic number.
100312155131 is a deficient number, since it is larger than the sum of its proper divisors (6097670149).
100312155131 is a wasteful number, since it uses less digits than its factorization.
100312155131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2915.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 100312155131 its reverse (131551213001), we get a palindrome (231863368132).
The spelling of 100312155131 in words is "one hundred billion, three hundred twelve million, one hundred fifty-five thousand, one hundred thirty-one".
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