100312300111 has 4 divisors (see below), whose sum is σ = 100315668672. Its totient is φ = 100308931552.

The previous prime is 100312300093. The next prime is 100312300133. The reversal of 100312300111 is 111003213001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111003213001 = 131 ⋅847352771.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100312300111 is a prime.

It is a super-2 number, since 2×100312300111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100312300091 and 100312300100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100312300511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1639210 + ... + 1699303.

It is an arithmetic number, because the mean of its divisors is an integer number (25078917168).

Almost surely, 2^100312300111 is an apocalyptic number.

100312300111 is a deficient number, since it is larger than the sum of its proper divisors (3368561).

100312300111 is an equidigital number, since it uses as much as digits as its factorization.

100312300111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3368560.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100312300111 its reverse (111003213001), we get a palindrome (211315513112).

The spelling of 100312300111 in words is "one hundred billion, three hundred twelve million, three hundred thousand, one hundred eleven".