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100313140243139 is a prime number
BaseRepresentation
bin10110110011101111111001…
…000101110010101011000011
3111011011211202012221001220122
4112303233321011302223003
5101122012302400240024
6553203115340530455
730062246062244435
oct2663577105625303
9434154665831818
10100313140243139
1129a6562256664a
12b301437850a2b
1343c864740a445
141aab279188655
15b8e595883d5e
hex5b3bf9172ac3

100313140243139 has 2 divisors, whose sum is σ = 100313140243140. Its totient is φ = 100313140243138.

The previous prime is 100313140243117. The next prime is 100313140243301. The reversal of 100313140243139 is 931342041313001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100313140243139 - 228 = 100312871807683 is a prime.

It is a super-2 number, since 2×1003131402431392 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100313140243099 and 100313140243108.

It is not a weakly prime, because it can be changed into another prime (100313140243639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50156570121569 + 50156570121570.

It is an arithmetic number, because the mean of its divisors is an integer number (50156570121570).

Almost surely, 2100313140243139 is an apocalyptic number.

100313140243139 is a deficient number, since it is larger than the sum of its proper divisors (1).

100313140243139 is an equidigital number, since it uses as much as digits as its factorization.

100313140243139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 100313140243139 in words is "one hundred trillion, three hundred thirteen billion, one hundred forty million, two hundred forty-three thousand, one hundred thirty-nine".