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1003132211993 is a prime number
BaseRepresentation
bin11101001100011110101…
…01101101001100011001
310112220021000020021120122
432212033111231030121
5112413403321240433
62044455500403025
7132321360054302
oct16461725551431
93486230207518
101003132211993
11357475a8914a
121424b6b46475
1373797191612
14367a24277a9
151b161724198
hexe98f56d319

1003132211993 has 2 divisors, whose sum is σ = 1003132211994. Its totient is φ = 1003132211992.

The previous prime is 1003132211969. The next prime is 1003132212007. The reversal of 1003132211993 is 3991122313001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 593573170969 + 409559041024 = 770437^2 + 639968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1003132211993 is a prime.

It is a super-5 number, since 5×10031322119935 (a number of 61 digits) contains 55555 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1003132211093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501566105996 + 501566105997.

It is an arithmetic number, because the mean of its divisors is an integer number (501566105997).

Almost surely, 21003132211993 is an apocalyptic number.

It is an amenable number.

1003132211993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003132211993 is an equidigital number, since it uses as much as digits as its factorization.

1003132211993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 35.

Adding to 1003132211993 its reverse (3991122313001), we get a palindrome (4994254524994).

The spelling of 1003132211993 in words is "one trillion, three billion, one hundred thirty-two million, two hundred eleven thousand, nine hundred ninety-three".