100314024211 has 2 divisors, whose sum is σ = 100314024212. Its totient is φ = 100314024210.

The previous prime is 100314024121. The next prime is 100314024247. The reversal of 100314024211 is 112420413001.

Together with previous prime (100314024121) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100314024211 is a prime.

It is not a weakly prime, because it can be changed into another prime (100314024511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157012105 + 50157012106.

It is an arithmetic number, because the mean of its divisors is an integer number (50157012106).

Almost surely, 2^100314024211 is an apocalyptic number.

100314024211 is a deficient number, since it is larger than the sum of its proper divisors (1).

100314024211 is an equidigital number, since it uses as much as digits as its factorization.

100314024211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 100314024211 its reverse (112420413001), we get a palindrome (212734437212).

The spelling of 100314024211 in words is "one hundred billion, three hundred fourteen million, twenty-four thousand, two hundred eleven".