Base | Representation |
---|---|
bin | 101110101101110001… |
… | …1010011111110100011 |
3 | 100120221111012210001101 |
4 | 1131123203103332203 |
5 | 3120423434400311 |
6 | 114030402415231 |
7 | 10151012616355 |
oct | 1353343237643 |
9 | 316844183041 |
10 | 100320231331 |
11 | 396001786a1 |
12 | 17539061517 |
13 | 95c9c72038 |
14 | 4bd97bd0d5 |
15 | 29223e2ec1 |
hex | 175b8d3fa3 |
100320231331 has 2 divisors, whose sum is σ = 100320231332. Its totient is φ = 100320231330.
The previous prime is 100320231289. The next prime is 100320231359. The reversal of 100320231331 is 133132023001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100320231331 - 217 = 100320100259 is a prime.
It is a super-2 number, since 2×1003202313312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100320231299 and 100320231308.
It is not a weakly prime, because it can be changed into another prime (100320231371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50160115665 + 50160115666.
It is an arithmetic number, because the mean of its divisors is an integer number (50160115666).
Almost surely, 2100320231331 is an apocalyptic number.
100320231331 is a deficient number, since it is larger than the sum of its proper divisors (1).
100320231331 is an equidigital number, since it uses as much as digits as its factorization.
100320231331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 100320231331 its reverse (133132023001), we get a palindrome (233452254332).
The spelling of 100320231331 in words is "one hundred billion, three hundred twenty million, two hundred thirty-one thousand, three hundred thirty-one".
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