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100323313000241 is a prime number
BaseRepresentation
bin10110110011111001010111…
…011011110001111100110001
3111011012211000011202200020012
4112303321113123301330301
5101122144121112001431
6553211521014224305
730063056135250422
oct2663712733617461
9434184004680205
10100323313000241
1129a69972846621
12b3033b6655095
1343c95a8b33b46
141aab96223b649
15b8e98d9b922b
hex5b3e576f1f31

100323313000241 has 2 divisors, whose sum is σ = 100323313000242. Its totient is φ = 100323313000240.

The previous prime is 100323313000181. The next prime is 100323313000283. The reversal of 100323313000241 is 142000313323001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83826750933025 + 16496562067216 = 9155695^2 + 4061596^2 .

It is a cyclic number.

It is not a de Polignac number, because 100323313000241 - 218 = 100323312738097 is a prime.

It is not a weakly prime, because it can be changed into another prime (100323313000441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50161656500120 + 50161656500121.

It is an arithmetic number, because the mean of its divisors is an integer number (50161656500121).

Almost surely, 2100323313000241 is an apocalyptic number.

It is an amenable number.

100323313000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

100323313000241 is an equidigital number, since it uses as much as digits as its factorization.

100323313000241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 100323313000241 its reverse (142000313323001), we get a palindrome (242323626323242).

The spelling of 100323313000241 in words is "one hundred trillion, three hundred twenty-three billion, three hundred thirteen million, two hundred forty-one", and thus it is an aban number.