Base | Representation |
---|---|
bin | 10110110011111001100101… |
… | …101111110011110111001011 |
3 | 111011012211121220121122001021 |
4 | 112303321211233303313023 |
5 | 101122200114100210404 |
6 | 553212000513133311 |
7 | 30063065112322102 |
oct | 2663714557636713 |
9 | 434184556548037 |
10 | 100323553131979 |
11 | 29a69a8634a101 |
12 | b303462b5a237 |
13 | 43c96167cc928 |
14 | 1aab9860a9039 |
15 | b8e9a4aee454 |
hex | 5b3e65bf3dcb |
100323553131979 has 2 divisors, whose sum is σ = 100323553131980. Its totient is φ = 100323553131978.
The previous prime is 100323553131931. The next prime is 100323553132073. The reversal of 100323553131979 is 979131355323001.
It is a weak prime.
It is an emirp because it is prime and its reverse (979131355323001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100323553131979 - 211 = 100323553129931 is a prime.
It is not a weakly prime, because it can be changed into another prime (100323553134979) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50161776565989 + 50161776565990.
It is an arithmetic number, because the mean of its divisors is an integer number (50161776565990).
Almost surely, 2100323553131979 is an apocalyptic number.
100323553131979 is a deficient number, since it is larger than the sum of its proper divisors (1).
100323553131979 is an equidigital number, since it uses as much as digits as its factorization.
100323553131979 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2296350, while the sum is 52.
The spelling of 100323553131979 in words is "one hundred trillion, three hundred twenty-three billion, five hundred fifty-three million, one hundred thirty-one thousand, nine hundred seventy-nine".
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