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10032402004143 = 33344134001381
BaseRepresentation
bin1001000111111101100111…
…0000011111100010101111
31022112002101100022121102220
42101333121300133202233
52303332324403113033
633200453304250423
72053550163004551
oct221773160374257
938462340277386
1010032402004143
113218799429342
12116041b170a13
1357a08905b53c
142697dc5994d1
15125e7488bbb3
hex91fd9c1f8af

10032402004143 has 4 divisors (see below), whose sum is σ = 13376536005528. Its totient is φ = 6688268002760.

The previous prime is 10032402004111. The next prime is 10032402004153. The reversal of 10032402004143 is 34140020423001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10032402004143 - 25 = 10032402004111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10032402004153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672067000688 + ... + 1672067000693.

It is an arithmetic number, because the mean of its divisors is an integer number (3344134001382).

Almost surely, 210032402004143 is an apocalyptic number.

10032402004143 is a deficient number, since it is larger than the sum of its proper divisors (3344134001385).

10032402004143 is an equidigital number, since it uses as much as digits as its factorization.

10032402004143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3344134001384.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 10032402004143 its reverse (34140020423001), we get a palindrome (44172422427144).

The spelling of 10032402004143 in words is "ten trillion, thirty-two billion, four hundred two million, four thousand, one hundred forty-three".

Divisors: 1 3 3344134001381 10032402004143