10033100301113 has 2 divisors, whose sum is σ = 10033100301114. Its totient is φ = 10033100301112.

The previous prime is 10033100300987. The next prime is 10033100301157. The reversal of 10033100301113 is 31110300133001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9535268453929 + 497831847184 = 3087923^2 + 705572^2 .

It is a cyclic number.

It is not a de Polignac number, because 10033100301113 - 2⁸ = 10033100300857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10033100301091 and 10033100301100.

It is not a weakly prime, because it can be changed into another prime (10033100304113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016550150556 + 5016550150557.

It is an arithmetic number, because the mean of its divisors is an integer number (5016550150557).

Almost surely, 2^{10033100301113} is an apocalyptic number.

It is an amenable number.

10033100301113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10033100301113 is an equidigital number, since it uses as much as digits as its factorization.

10033100301113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10033100301113 its reverse (31110300133001), we get a palindrome (41143400434114).

The spelling of 10033100301113 in words is "ten trillion, thirty-three billion, one hundred million, three hundred one thousand, one hundred thirteen".