Base | Representation |
---|---|
bin | 1001001000000000001101… |
… | …1000101010010101001011 |
3 | 1022112011012000110210101011 |
4 | 2102000003120222111023 |
5 | 2303340242200244242 |
6 | 33201050453304351 |
7 | 2053603403165122 |
oct | 222000330522513 |
9 | 38464160423334 |
10 | 10033100399947 |
11 | 3219017682459 |
12 | 11605950350b7 |
13 | 57a16a9586b1 |
14 | 269867236ab9 |
15 | 125eb5d43d17 |
hex | 9200362a54b |
10033100399947 has 2 divisors, whose sum is σ = 10033100399948. Its totient is φ = 10033100399946.
The previous prime is 10033100399893. The next prime is 10033100400101. The reversal of 10033100399947 is 74999300133001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10033100399947 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10033100399947.
It is not a weakly prime, because it can be changed into another prime (10033100399447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016550199973 + 5016550199974.
It is an arithmetic number, because the mean of its divisors is an integer number (5016550199974).
Almost surely, 210033100399947 is an apocalyptic number.
10033100399947 is a deficient number, since it is larger than the sum of its proper divisors (1).
10033100399947 is an equidigital number, since it uses as much as digits as its factorization.
10033100399947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 551124, while the sum is 49.
The spelling of 10033100399947 in words is "ten trillion, thirty-three billion, one hundred million, three hundred ninety-nine thousand, nine hundred forty-seven".
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