Base | Representation |
---|---|
bin | 11101001100110011111… |
… | …11110100001111101001 |
3 | 10112220201110200211021112 |
4 | 32212121333310033221 |
5 | 112414240110214311 |
6 | 2044525325120105 |
7 | 132325660661363 |
oct | 16463177641751 |
9 | 3486643624245 |
10 | 1003311023081 |
11 | 357557a09604 |
12 | 1425469b9035 |
13 | 737c523a2b3 |
14 | 367bc091d33 |
15 | 1b17229528b |
hex | e999ff43e9 |
1003311023081 has 2 divisors, whose sum is σ = 1003311023082. Its totient is φ = 1003311023080.
The previous prime is 1003311023053. The next prime is 1003311023111. The reversal of 1003311023081 is 1803201133001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 624390753856 + 378920269225 = 790184^2 + 615565^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1003311023081 is a prime.
It is a super-2 number, since 2×10033110230812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1003311043081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501655511540 + 501655511541.
It is an arithmetic number, because the mean of its divisors is an integer number (501655511541).
Almost surely, 21003311023081 is an apocalyptic number.
It is an amenable number.
1003311023081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003311023081 is an equidigital number, since it uses as much as digits as its factorization.
1003311023081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1003311023081 its reverse (1803201133001), we get a palindrome (2806512156082).
The spelling of 1003311023081 in words is "one trillion, three billion, three hundred eleven million, twenty-three thousand, eighty-one".
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