Base | Representation |
---|---|
bin | 10010101100000010… |
… | …10100110010000001 |
3 | 221220020002102120011 |
4 | 21112001110302001 |
5 | 131021434404213 |
6 | 4335324344521 |
7 | 503426063545 |
oct | 112601246201 |
9 | 27806072504 |
10 | 10033122433 |
11 | 4289488424 |
12 | 1b400a5141 |
13 | c3b816749 |
14 | 6b2705a25 |
15 | 3dac5203d |
hex | 256054c81 |
10033122433 has 2 divisors, whose sum is σ = 10033122434. Its totient is φ = 10033122432.
The previous prime is 10033122343. The next prime is 10033122461. The reversal of 10033122433 is 33422133001.
Together with previous prime (10033122343) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9871018609 + 162103824 = 99353^2 + 12732^2 .
It is a cyclic number.
It is not a de Polignac number, because 10033122433 - 217 = 10032991361 is a prime.
It is not a weakly prime, because it can be changed into another prime (10033122133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016561216 + 5016561217.
It is an arithmetic number, because the mean of its divisors is an integer number (5016561217).
Almost surely, 210033122433 is an apocalyptic number.
It is an amenable number.
10033122433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10033122433 is an equidigital number, since it uses as much as digits as its factorization.
10033122433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 10033122433 its reverse (33422133001), we get a palindrome (43455255434).
The spelling of 10033122433 in words is "ten billion, thirty-three million, one hundred twenty-two thousand, four hundred thirty-three".
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