Base | Representation |
---|---|
bin | 11101001100110101001… |
… | …11001011110011100001 |
3 | 10112220202012010010211012 |
4 | 32212122213023303201 |
5 | 112414300230440301 |
6 | 2044530334230305 |
7 | 132326144463242 |
oct | 16463247136341 |
9 | 3486665103735 |
10 | 1003321343201 |
11 | 357562818231 |
12 | 14254a355395 |
13 | 737c7411788 |
14 | 367bd5bacc9 |
15 | 1b173132ebb |
hex | e99a9cbce1 |
1003321343201 has 2 divisors, whose sum is σ = 1003321343202. Its totient is φ = 1003321343200.
The previous prime is 1003321343179. The next prime is 1003321343237. The reversal of 1003321343201 is 1023431233001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 691851314176 + 311470029025 = 831776^2 + 558095^2 .
It is an emirp because it is prime and its reverse (1023431233001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1003321343201 is a prime.
It is not a weakly prime, because it can be changed into another prime (1003321349201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501660671600 + 501660671601.
It is an arithmetic number, because the mean of its divisors is an integer number (501660671601).
Almost surely, 21003321343201 is an apocalyptic number.
It is an amenable number.
1003321343201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003321343201 is an equidigital number, since it uses as much as digits as its factorization.
1003321343201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1003321343201 its reverse (1023431233001), we get a palindrome (2026752576202).
The spelling of 1003321343201 in words is "one trillion, three billion, three hundred twenty-one million, three hundred forty-three thousand, two hundred one".
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