Base | Representation |
---|---|
bin | 11101001100110110011… |
… | …11110110100101101001 |
3 | 10112220202221011202222001 |
4 | 32212123033312211221 |
5 | 112414310443113301 |
6 | 2044531354531001 |
7 | 132326334215002 |
oct | 16463317664551 |
9 | 3486687152861 |
10 | 1003332004201 |
11 | 357568839a7a |
12 | 142551a36a61 |
13 | 737c96a5167 |
14 | 367c0b941a9 |
15 | 1b17403bc01 |
hex | e99b3f6969 |
1003332004201 has 2 divisors, whose sum is σ = 1003332004202. Its totient is φ = 1003332004200.
The previous prime is 1003332004187. The next prime is 1003332004219. The reversal of 1003332004201 is 1024002333001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 526569373801 + 476762630400 = 725651^2 + 690480^2 .
It is a cyclic number.
It is not a de Polignac number, because 1003332004201 - 233 = 994742069609 is a prime.
It is a super-2 number, since 2×10033320042012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1003332004601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501666002100 + 501666002101.
It is an arithmetic number, because the mean of its divisors is an integer number (501666002101).
Almost surely, 21003332004201 is an apocalyptic number.
It is an amenable number.
1003332004201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003332004201 is an equidigital number, since it uses as much as digits as its factorization.
1003332004201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1003332004201 its reverse (1024002333001), we get a palindrome (2027334337202).
The spelling of 1003332004201 in words is "one trillion, three billion, three hundred thirty-two million, four thousand, two hundred one".
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