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100335314122649 is a prime number
BaseRepresentation
bin10110110100000100100010…
…110000011011011110011001
3111011020221222112222212020022
4112310010202300123132121
5101122343210403411044
6553221223524040225
730063662422150454
oct2664044260333631
9434227875885208
10100335314122649
1129a73a710a4501
12b3057a5833075
1343ca76c29c4c8
141aac38006c49b
15b8ee423ac3ee
hex5b4122c1b799

100335314122649 has 2 divisors, whose sum is σ = 100335314122650. Its totient is φ = 100335314122648.

The previous prime is 100335314122633. The next prime is 100335314122663. The reversal of 100335314122649 is 946221413533001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70849979721049 + 29485334401600 = 8417243^2 + 5430040^2 .

It is an emirp because it is prime and its reverse (946221413533001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100335314122649 - 24 = 100335314122633 is a prime.

It is a super-2 number, since 2×1003353141226492 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100335314142649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50167657061324 + 50167657061325.

It is an arithmetic number, because the mean of its divisors is an integer number (50167657061325).

Almost surely, 2100335314122649 is an apocalyptic number.

It is an amenable number.

100335314122649 is a deficient number, since it is larger than the sum of its proper divisors (1).

100335314122649 is an equidigital number, since it uses as much as digits as its factorization.

100335314122649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 44.

The spelling of 100335314122649 in words is "one hundred trillion, three hundred thirty-five billion, three hundred fourteen million, one hundred twenty-two thousand, six hundred forty-nine".