100341114433 has 8 divisors (see below), whose sum is σ = 118374771200. Its totient is φ = 83232260640.

The previous prime is 100341114413. The next prime is 100341114457. The reversal of 100341114433 is 334411143001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100341114433 - 2¹³ = 100341106241 is a prime.

It is a super-2 number, since 2×100341114433² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100341114398 and 100341114407.

It is not an unprimeable number, because it can be changed into a prime (100341114413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 231200508 + ... + 231200941.

It is an arithmetic number, because the mean of its divisors is an integer number (14796846400).

Almost surely, 2^100341114433 is an apocalyptic number.

It is an amenable number.

100341114433 is a deficient number, since it is larger than the sum of its proper divisors (18033656767).

100341114433 is an equidigital number, since it uses as much as digits as its factorization.

100341114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462401487.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 100341114433 its reverse (334411143001), we get a palindrome (434752257434).

The spelling of 100341114433 in words is "one hundred billion, three hundred forty-one million, one hundred fourteen thousand, four hundred thirty-three".