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100342441231 = 172347205679
BaseRepresentation
bin101110101110011100…
…0000010010100001111
3100121000001000011022021
41131130320002110033
53121000131104411
6114032514431011
710151402451304
oct1353470022417
9317001004267
10100342441231
113961176828a
1217544592467
13960174a2a6
144bdc7210ab
15292432da71
hex175ce0250f

100342441231 has 6 divisors (see below), whose sum is σ = 106592143760. Its totient is φ = 94439944416.

The previous prime is 100342441219. The next prime is 100342441253. The reversal of 100342441231 is 132144243001.

It is not a de Polignac number, because 100342441231 - 213 = 100342433039 is a prime.

It is a super-2 number, since 2×1003424412312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100342441196 and 100342441205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100342441201) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 173602551 + ... + 173603128.

Almost surely, 2100342441231 is an apocalyptic number.

100342441231 is a deficient number, since it is larger than the sum of its proper divisors (6249702529).

100342441231 is an equidigital number, since it uses as much as digits as its factorization.

100342441231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347205713 (or 347205696 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 100342441231 its reverse (132144243001), we get a palindrome (232486684232).

The spelling of 100342441231 in words is "one hundred billion, three hundred forty-two million, four hundred forty-one thousand, two hundred thirty-one".

Divisors: 1 17 289 347205679 5902496543 100342441231