Base | Representation |
---|---|
bin | 101110101110011111… |
… | …0011100111110111011 |
3 | 100121000011011121200222 |
4 | 1131130332130332323 |
5 | 3121001043421243 |
6 | 114033014450255 |
7 | 10151422655333 |
oct | 1353476347673 |
9 | 317004147628 |
10 | 100344123323 |
11 | 39612707044 |
12 | 1754506398b |
13 | 9601bb8b02 |
14 | 4bdca3c0c3 |
15 | 2924562168 |
hex | 175cf9cfbb |
100344123323 has 2 divisors, whose sum is σ = 100344123324. Its totient is φ = 100344123322.
The previous prime is 100344123301. The next prime is 100344123343. The reversal of 100344123323 is 323321443001.
It is a strong prime.
It is an emirp because it is prime and its reverse (323321443001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100344123323 - 210 = 100344122299 is a prime.
It is a super-2 number, since 2×1003441233232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100344123292 and 100344123301.
It is not a weakly prime, because it can be changed into another prime (100344123343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50172061661 + 50172061662.
It is an arithmetic number, because the mean of its divisors is an integer number (50172061662).
Almost surely, 2100344123323 is an apocalyptic number.
100344123323 is a deficient number, since it is larger than the sum of its proper divisors (1).
100344123323 is an equidigital number, since it uses as much as digits as its factorization.
100344123323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 100344123323 its reverse (323321443001), we get a palindrome (423665566324).
The spelling of 100344123323 in words is "one hundred billion, three hundred forty-four million, one hundred twenty-three thousand, three hundred twenty-three".
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